Base | Representation |
---|---|
bin | 1011000000010100111010… |
… | …0101111010011001010111 |
3 | 1120211202211122000120111112 |
4 | 2300011032211322121113 |
5 | 3041222243301343244 |
6 | 41422435115525235 |
7 | 2356133156105552 |
oct | 260051645723127 |
9 | 46752748016445 |
10 | 12100241434199 |
11 | 3945757922aa6 |
12 | 143513645981b |
13 | 69a081232ba9 |
14 | 2db924b29699 |
15 | 15eb4d44b39e |
hex | b014e97a657 |
12100241434199 has 2 divisors, whose sum is σ = 12100241434200. Its totient is φ = 12100241434198.
The previous prime is 12100241434163. The next prime is 12100241434217. The reversal of 12100241434199 is 99143414200121.
12100241434199 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is an emirp because it is prime and its reverse (99143414200121) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12100241434199 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12100241434159) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6050120717099 + 6050120717100.
It is an arithmetic number, because the mean of its divisors is an integer number (6050120717100).
Almost surely, 212100241434199 is an apocalyptic number.
12100241434199 is a deficient number, since it is larger than the sum of its proper divisors (1).
12100241434199 is an equidigital number, since it uses as much as digits as its factorization.
12100241434199 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 62208, while the sum is 41.
The spelling of 12100241434199 in words is "twelve trillion, one hundred billion, two hundred forty-one million, four hundred thirty-four thousand, one hundred ninety-nine".
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