Search a number
-
+
121010002013 is a prime number
BaseRepresentation
bin111000010110011000…
…0100001100001011101
3102120100101200000210102
41300230300201201131
53440312030031023
6131331412150445
711512512021455
oct1605460414135
9376311600712
10121010002013
1147357a9a62a
121b552008425
13b546516cb4
145bdd538d65
1532339b0628
hex1c2cc2185d

121010002013 has 2 divisors, whose sum is σ = 121010002014. Its totient is φ = 121010002012.

The previous prime is 121010001989. The next prime is 121010002019. The reversal of 121010002013 is 310200010121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 89743982329 + 31266019684 = 299573^2 + 176822^2 .

It is an emirp because it is prime and its reverse (310200010121) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 121010002013 - 218 = 121009739869 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 121010001985 and 121010002003.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (121010002019) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60505001006 + 60505001007.

It is an arithmetic number, because the mean of its divisors is an integer number (60505001007).

Almost surely, 2121010002013 is an apocalyptic number.

It is an amenable number.

121010002013 is a deficient number, since it is larger than the sum of its proper divisors (1).

121010002013 is an equidigital number, since it uses as much as digits as its factorization.

121010002013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12, while the sum is 11.

Adding to 121010002013 its reverse (310200010121), we get a palindrome (431210012134).

The spelling of 121010002013 in words is "one hundred twenty-one billion, ten million, two thousand, thirteen".