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121010012113 is a prime number
BaseRepresentation
bin111000010110011000…
…0100011111111010001
3102120100101200112122111
41300230300203333101
53440312030341423
6131331412305321
711512512063064
oct1605460437721
9376311615574
10121010012113
1147357aa7181
121b552012241
13b54651b783
145bdd53c8db
1532339b360d
hex1c2cc23fd1

121010012113 has 2 divisors, whose sum is σ = 121010012114. Its totient is φ = 121010012112.

The previous prime is 121010012077. The next prime is 121010012129. The reversal of 121010012113 is 311210010121.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 66968641089 + 54041371024 = 258783^2 + 232468^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-121010012113 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 121010012093 and 121010012102.

It is not a weakly prime, because it can be changed into another prime (121010012413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60505006056 + 60505006057.

It is an arithmetic number, because the mean of its divisors is an integer number (60505006057).

Almost surely, 2121010012113 is an apocalyptic number.

It is an amenable number.

121010012113 is a deficient number, since it is larger than the sum of its proper divisors (1).

121010012113 is an equidigital number, since it uses as much as digits as its factorization.

121010012113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12, while the sum is 13.

Adding to 121010012113 its reverse (311210010121), we get a palindrome (432220022234).

The spelling of 121010012113 in words is "one hundred twenty-one billion, ten million, twelve thousand, one hundred thirteen".