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1210101999949 is a prime number
BaseRepresentation
bin10001100110111111101…
…100110010100101001101
311021200111002101212201201
4101212333230302211031
5124311242102444244
62323525125305501
7153266312166643
oct21467754624515
94250432355651
101210101999949
11427224039187
12176638865291
138a15c46907b
14427d803d193
15217269e5ad4
hex119bfb3294d

1210101999949 has 2 divisors, whose sum is σ = 1210101999950. Its totient is φ = 1210101999948.

The previous prime is 1210101999929. The next prime is 1210102000067. The reversal of 1210101999949 is 9499991010121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1148948172100 + 61153827849 = 1071890^2 + 247293^2 .

It is a cyclic number.

It is not a de Polignac number, because 1210101999949 - 215 = 1210101967181 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1210101999949.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1210101999919) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605050999974 + 605050999975.

It is an arithmetic number, because the mean of its divisors is an integer number (605050999975).

Almost surely, 21210101999949 is an apocalyptic number.

It is an amenable number.

1210101999949 is a deficient number, since it is larger than the sum of its proper divisors (1).

1210101999949 is an equidigital number, since it uses as much as digits as its factorization.

1210101999949 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 472392, while the sum is 55.

The spelling of 1210101999949 in words is "one trillion, two hundred ten billion, one hundred one million, nine hundred ninety-nine thousand, nine hundred forty-nine".