Base | Representation |
---|---|
bin | 11011100000111011100010… |
… | …100110000010100001101111 |
3 | 120212110110111121112101101002 |
4 | 123200323202212002201233 |
5 | 111330112402304021033 |
6 | 1105211153443510515 |
7 | 34326461550316646 |
oct | 3340734246024157 |
9 | 525413447471332 |
10 | 121010210220143 |
11 | 35615161a37672 |
12 | 116a470a68843b |
13 | 526a2a1b07a9a |
14 | 21c4cd551c35d |
15 | decb474523e8 |
hex | 6e0ee298286f |
121010210220143 has 2 divisors, whose sum is σ = 121010210220144. Its totient is φ = 121010210220142.
The previous prime is 121010210220047. The next prime is 121010210220149. The reversal of 121010210220143 is 341022012010121.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 121010210220143 - 232 = 121005915252847 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (121010210220149) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60505105110071 + 60505105110072.
It is an arithmetic number, because the mean of its divisors is an integer number (60505105110072).
Almost surely, 2121010210220143 is an apocalyptic number.
121010210220143 is a deficient number, since it is larger than the sum of its proper divisors (1).
121010210220143 is an equidigital number, since it uses as much as digits as its factorization.
121010210220143 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 192, while the sum is 20.
Adding to 121010210220143 its reverse (341022012010121), we get a palindrome (462032222230264).
The spelling of 121010210220143 in words is "one hundred twenty-one trillion, ten billion, two hundred ten million, two hundred twenty thousand, one hundred forty-three".
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