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121010330112013 is a prime number
BaseRepresentation
bin11011100000111011101001…
…101111011001000000001101
3120212110110210222010112002201
4123200323221233121000031
5111330113124002041023
61105211213405321501
734326464534350636
oct3340735157310015
9525413728115081
10121010330112013
1135615213685161
12116a4742866291
13526a2c08c4714
1421c4d0740a88d
15decb52c35bad
hex6e0ee9bd900d

121010330112013 has 2 divisors, whose sum is σ = 121010330112014. Its totient is φ = 121010330112012.

The previous prime is 121010330111977. The next prime is 121010330112043. The reversal of 121010330112013 is 310211033010121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 86105074435524 + 34905255676489 = 9279282^2 + 5908067^2 .

It is a cyclic number.

It is not a de Polignac number, because 121010330112013 - 213 = 121010330103821 is a prime.

It is a super-2 number, since 2×1210103301120132 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (121010330112043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60505165056006 + 60505165056007.

It is an arithmetic number, because the mean of its divisors is an integer number (60505165056007).

Almost surely, 2121010330112013 is an apocalyptic number.

It is an amenable number.

121010330112013 is a deficient number, since it is larger than the sum of its proper divisors (1).

121010330112013 is an equidigital number, since it uses as much as digits as its factorization.

121010330112013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 121010330112013 its reverse (310211033010121), we get a palindrome (431221363122134).

The spelling of 121010330112013 in words is "one hundred twenty-one trillion, ten billion, three hundred thirty million, one hundred twelve thousand, thirteen".