Base | Representation |
---|---|
bin | 10001100111000000001… |
… | …011011110000000000010 |
3 | 11021200111122112110111200 |
4 | 101213000023132000002 |
5 | 124311301132321424 |
6 | 2323530013522030 |
7 | 153266440433331 |
oct | 21470013360002 |
9 | 4250448473450 |
10 | 1210110042114 |
11 | 4272286313a6 |
12 | 17663b4a3316 |
13 | 8a16102374c |
14 | 427d9133d18 |
15 | 217275838c9 |
hex | 119c02de002 |
1210110042114 has 24 divisors (see below), whose sum is σ = 2625396339072. Its totient is φ = 402832899000.
The previous prime is 1210110042107. The next prime is 1210110042121. The reversal of 1210110042114 is 4112400110121.
1210110042114 is a `hidden beast` number, since 121 + 0 + 110 + 0 + 421 + 14 = 666.
It is an interprime number because it is at equal distance from previous prime (1210110042107) and next prime (1210110042121).
It is a Harshad number since it is a multiple of its sum of digits (18).
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 44745694 + ... + 44772729.
It is an arithmetic number, because the mean of its divisors is an integer number (109391514128).
Almost surely, 21210110042114 is an apocalyptic number.
1210110042114 is an abundant number, since it is smaller than the sum of its proper divisors (1415286296958).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1210110042114 is a wasteful number, since it uses less digits than its factorization.
1210110042114 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 89519182 (or 89519179 counting only the distinct ones).
The product of its (nonzero) digits is 64, while the sum is 18.
Adding to 1210110042114 its reverse (4112400110121), we get a palindrome (5322510152235).
The spelling of 1210110042114 in words is "one trillion, two hundred ten billion, one hundred ten million, forty-two thousand, one hundred fourteen".
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