Base | Representation |
---|---|
bin | 1011000000011000001011… |
… | …1101110010111001000011 |
3 | 1120211212002212101221022011 |
4 | 2300012002331302321003 |
5 | 3041231043222011042 |
6 | 41423102224553351 |
7 | 2356164015532165 |
oct | 260060275627103 |
9 | 46755085357264 |
10 | 12101120110147 |
11 | 3946068910272 |
12 | 1435340782857 |
13 | 69a1912a15a3 |
14 | 2db9a96d4935 |
15 | 15eba0664a17 |
hex | b0182f72e43 |
12101120110147 has 2 divisors, whose sum is σ = 12101120110148. Its totient is φ = 12101120110146.
The previous prime is 12101120110111. The next prime is 12101120110153. The reversal of 12101120110147 is 74101102110121.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12101120110147 - 219 = 12101119585859 is a prime.
It is not a weakly prime, because it can be changed into another prime (12101120110447) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6050560055073 + 6050560055074.
It is an arithmetic number, because the mean of its divisors is an integer number (6050560055074).
Almost surely, 212101120110147 is an apocalyptic number.
12101120110147 is a deficient number, since it is larger than the sum of its proper divisors (1).
12101120110147 is an equidigital number, since it uses as much as digits as its factorization.
12101120110147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 112, while the sum is 22.
Adding to 12101120110147 its reverse (74101102110121), we get a palindrome (86202222220268).
The spelling of 12101120110147 in words is "twelve trillion, one hundred one billion, one hundred twenty million, one hundred ten thousand, one hundred forty-seven".
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