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12101120118953 is a prime number
BaseRepresentation
bin1011000000011000001011…
…1101110101000010101001
31120211212002212102101101022
42300012002331311002221
53041231043222301303
641423102225102225
72356164015566645
oct260060275650251
946755085371338
1012101120118953
113946068916948
121435340787975
1369a1912a55b8
142db9a96d7c25
1515eba0667438
hexb0182f750a9

12101120118953 has 2 divisors, whose sum is σ = 12101120118954. Its totient is φ = 12101120118952.

The previous prime is 12101120118931. The next prime is 12101120118977. The reversal of 12101120118953 is 35981102110121.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11805910456729 + 295209662224 = 3435973^2 + 543332^2 .

It is a cyclic number.

It is not a de Polignac number, because 12101120118953 - 232 = 12096825151657 is a prime.

It is not a weakly prime, because it can be changed into another prime (12101120118653) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6050560059476 + 6050560059477.

It is an arithmetic number, because the mean of its divisors is an integer number (6050560059477).

Almost surely, 212101120118953 is an apocalyptic number.

It is an amenable number.

12101120118953 is a deficient number, since it is larger than the sum of its proper divisors (1).

12101120118953 is an equidigital number, since it uses as much as digits as its factorization.

12101120118953 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4320, while the sum is 35.

The spelling of 12101120118953 in words is "twelve trillion, one hundred one billion, one hundred twenty million, one hundred eighteen thousand, nine hundred fifty-three".