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12101154493 is a prime number
BaseRepresentation
bin10110100010100100…
…01111011010111101
31011020100110100020011
423101102033122331
5144240343420433
65320441423221
7605610054541
oct132122173275
934210410204
1012101154493
11514a87152a
12241879ab11
1311ab0c095c
1482b22da21
154ac5a23cd
hex2d148f6bd

12101154493 has 2 divisors, whose sum is σ = 12101154494. Its totient is φ = 12101154492.

The previous prime is 12101154479. The next prime is 12101154497. The reversal of 12101154493 is 39445110121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11976675844 + 124478649 = 109438^2 + 11157^2 .

It is an emirp because it is prime and its reverse (39445110121) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12101154493 - 229 = 11564283581 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12101154497) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6050577246 + 6050577247.

It is an arithmetic number, because the mean of its divisors is an integer number (6050577247).

Almost surely, 212101154493 is an apocalyptic number.

It is an amenable number.

12101154493 is a deficient number, since it is larger than the sum of its proper divisors (1).

12101154493 is an equidigital number, since it uses as much as digits as its factorization.

12101154493 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4320, while the sum is 31.

The spelling of 12101154493 in words is "twelve billion, one hundred one million, one hundred fifty-four thousand, four hundred ninety-three".