Base | Representation |
---|---|
bin | 10001100111000000110… |
… | …101110001010010001011 |
3 | 11021200112102101211210121 |
4 | 101213000311301102023 |
5 | 124311312002144042 |
6 | 2323531051324111 |
7 | 153266633620015 |
oct | 21470065612213 |
9 | 4250472354717 |
10 | 1210121131147 |
11 | 427233915795 |
12 | 176643150637 |
13 | 8a163406bc6 |
14 | 427da7bd1b5 |
15 | 21728524367 |
hex | 119c0d7148b |
1210121131147 has 2 divisors, whose sum is σ = 1210121131148. Its totient is φ = 1210121131146.
The previous prime is 1210121130971. The next prime is 1210121131157. The reversal of 1210121131147 is 7411311210121.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1210121131147 - 211 = 1210121129099 is a prime.
It is not a weakly prime, because it can be changed into another prime (1210121131157) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605060565573 + 605060565574.
It is an arithmetic number, because the mean of its divisors is an integer number (605060565574).
Almost surely, 21210121131147 is an apocalyptic number.
1210121131147 is a deficient number, since it is larger than the sum of its proper divisors (1).
1210121131147 is an equidigital number, since it uses as much as digits as its factorization.
1210121131147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 336, while the sum is 25.
Adding to 1210121131147 its reverse (7411311210121), we get a palindrome (8621432341268).
The spelling of 1210121131147 in words is "one trillion, two hundred ten billion, one hundred twenty-one million, one hundred thirty-one thousand, one hundred forty-seven".
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