Base | Representation |
---|---|
bin | 11011100000111110011101… |
… | …010110010010101000100011 |
3 | 120212110202120222012222221011 |
4 | 123200332131112102220203 |
5 | 111330140311404244303 |
6 | 1105212432411241351 |
7 | 34326632314216036 |
oct | 3340763526225043 |
9 | 525422528188834 |
10 | 121013343431203 |
11 | 3561651a6124a3 |
12 | 116a5243a49257 |
13 | 526a680c90522 |
14 | 21c51116bd01d |
15 | decc7c55b16d |
hex | 6e0f9d592a23 |
121013343431203 has 2 divisors, whose sum is σ = 121013343431204. Its totient is φ = 121013343431202.
The previous prime is 121013343431111. The next prime is 121013343431243. The reversal of 121013343431203 is 302134343310121.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-121013343431203 is a prime.
It is not a weakly prime, because it can be changed into another prime (121013343431243) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60506671715601 + 60506671715602.
It is an arithmetic number, because the mean of its divisors is an integer number (60506671715602).
Almost surely, 2121013343431203 is an apocalyptic number.
121013343431203 is a deficient number, since it is larger than the sum of its proper divisors (1).
121013343431203 is an equidigital number, since it uses as much as digits as its factorization.
121013343431203 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15552, while the sum is 31.
Adding to 121013343431203 its reverse (302134343310121), we get a palindrome (423147686741324).
The spelling of 121013343431203 in words is "one hundred twenty-one trillion, thirteen billion, three hundred forty-three million, four hundred thirty-one thousand, two hundred three".
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