Base | Representation |
---|---|
bin | 11011100000111110011101… |
… | …010110010010100111000111 |
3 | 120212110202120222012222210202 |
4 | 123200332131112102213013 |
5 | 111330140311404243421 |
6 | 1105212432411241115 |
7 | 34326632314215545 |
oct | 3340763526224707 |
9 | 525422528188722 |
10 | 121013343431111 |
11 | 3561651a61241a |
12 | 116a5243a4919b |
13 | 526a680c90481 |
14 | 21c51116bcd95 |
15 | decc7c55b10b |
hex | 6e0f9d5929c7 |
121013343431111 has 2 divisors, whose sum is σ = 121013343431112. Its totient is φ = 121013343431110.
The previous prime is 121013343431107. The next prime is 121013343431203. The reversal of 121013343431111 is 111134343310121.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 121013343431111 - 22 = 121013343431107 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (121013343433111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60506671715555 + 60506671715556.
It is an arithmetic number, because the mean of its divisors is an integer number (60506671715556).
Almost surely, 2121013343431111 is an apocalyptic number.
121013343431111 is a deficient number, since it is larger than the sum of its proper divisors (1).
121013343431111 is an equidigital number, since it uses as much as digits as its factorization.
121013343431111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2592, while the sum is 29.
Adding to 121013343431111 its reverse (111134343310121), we get a palindrome (232147686741232).
The spelling of 121013343431111 in words is "one hundred twenty-one trillion, thirteen billion, three hundred forty-three million, four hundred thirty-one thousand, one hundred eleven".
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