Base | Representation |
---|---|
bin | 10110100010100110… |
… | …10011000010000011 |
3 | 1011020100222102002222 |
4 | 23101103103002003 |
5 | 144240431301202 |
6 | 5320451401255 |
7 | 605612320121 |
oct | 132123230203 |
9 | 34210872088 |
10 | 12101431427 |
11 | 514aa405a8 |
12 | 24188b322b |
13 | 11ab189a17 |
14 | 82b2a2911 |
15 | 4ac6094a2 |
hex | 2d14d3083 |
12101431427 has 2 divisors, whose sum is σ = 12101431428. Its totient is φ = 12101431426.
The previous prime is 12101431421. The next prime is 12101431429. The reversal of 12101431427 is 72413410121.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12101431427 - 24 = 12101431411 is a prime.
Together with 12101431429, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 12101431396 and 12101431405.
It is not a weakly prime, because it can be changed into another prime (12101431421) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6050715713 + 6050715714.
It is an arithmetic number, because the mean of its divisors is an integer number (6050715714).
Almost surely, 212101431427 is an apocalyptic number.
12101431427 is a deficient number, since it is larger than the sum of its proper divisors (1).
12101431427 is an equidigital number, since it uses as much as digits as its factorization.
12101431427 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1344, while the sum is 26.
Adding to 12101431427 its reverse (72413410121), we get a palindrome (84514841548).
The spelling of 12101431427 in words is "twelve billion, one hundred one million, four hundred thirty-one thousand, four hundred twenty-seven".
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