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121020022100120 = 235111346194748463
BaseRepresentation
bin11011100001000100101011…
…011011011001000010011000
3120212111101211102022112100012
4123201010223123121002120
5111330243001124200440
61105215455230301052
734330256652034013
oct3341045333310230
9525441742275305
10121020022100120
1135619337543290
12116a65a8657788
13526b1a683a420
1421c55866b237a
15ded01da50e65
hex6e112b6d9098

121020022100120 has 256 divisors, whose sum is σ = 320938161223680. Its totient is φ = 40490349926400.

The previous prime is 121020022100083. The next prime is 121020022100137. The reversal of 121020022100120 is 21001220020121.

It is a super-2 number, since 2×1210200221001202 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 121020022100095 and 121020022100104.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 2497139009 + ... + 2497187471.

It is an arithmetic number, because the mean of its divisors is an integer number (1253664692280).

Almost surely, 2121020022100120 is an apocalyptic number.

121020022100120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 121020022100120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (160469080611840).

121020022100120 is an abundant number, since it is smaller than the sum of its proper divisors (199918139123560).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

121020022100120 is a wasteful number, since it uses less digits than its factorization.

121020022100120 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 49906 (or 49902 counting only the distinct ones).

The product of its (nonzero) digits is 32, while the sum is 14.

Adding to 121020022100120 its reverse (21001220020121), we get a palindrome (142021242120241).

The spelling of 121020022100120 in words is "one hundred twenty-one trillion, twenty billion, twenty-two million, one hundred thousand, one hundred twenty".