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121020111020173 is a prime number
BaseRepresentation
bin11011100001000100110000…
…101110100110000010001101
3120212111102001121122010201111
4123201010300232212002031
5111330243141410121143
61105215512124212021
734330262111611111
oct3341046056460215
9525442047563644
10121020111020173
1135619382757232
12116a661239a011
13526b1bc0a1941
1421c559441b741
15ded02676799d
hex6e1130ba608d

121020111020173 has 2 divisors, whose sum is σ = 121020111020174. Its totient is φ = 121020111020172.

The previous prime is 121020111020141. The next prime is 121020111020197. The reversal of 121020111020173 is 371020111020121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 71024492325609 + 49995618694564 = 8427603^2 + 7070758^2 .

It is a cyclic number.

It is not a de Polignac number, because 121020111020173 - 25 = 121020111020141 is a prime.

It is a super-3 number, since 3×1210201110201733 (a number of 43 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (121020111620173) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60510055510086 + 60510055510087.

It is an arithmetic number, because the mean of its divisors is an integer number (60510055510087).

Almost surely, 2121020111020173 is an apocalyptic number.

It is an amenable number.

121020111020173 is a deficient number, since it is larger than the sum of its proper divisors (1).

121020111020173 is an equidigital number, since it uses as much as digits as its factorization.

121020111020173 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 168, while the sum is 22.

Adding to 121020111020173 its reverse (371020111020121), we get a palindrome (492040222040294).

The spelling of 121020111020173 in words is "one hundred twenty-one trillion, twenty billion, one hundred eleven million, twenty thousand, one hundred seventy-three".