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12102111001147 is a prime number
BaseRepresentation
bin1011000000011011111000…
…0001101111101000111011
31120211221122220221102012211
42300012332001233220323
53041240110404014042
641423344423115551
72356230410134216
oct260067601575073
946757586842184
1012102111001147
113946527182352
1214355785a2bb7
1369a2bb66c61b
142dba6115077d
1515ec0c647017
hexb01be06fa3b

12102111001147 has 2 divisors, whose sum is σ = 12102111001148. Its totient is φ = 12102111001146.

The previous prime is 12102111001109. The next prime is 12102111001177. The reversal of 12102111001147 is 74110011120121.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12102111001147 is a prime.

It is a super-2 number, since 2×121021110011472 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (12102111001177) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6051055500573 + 6051055500574.

It is an arithmetic number, because the mean of its divisors is an integer number (6051055500574).

Almost surely, 212102111001147 is an apocalyptic number.

12102111001147 is a deficient number, since it is larger than the sum of its proper divisors (1).

12102111001147 is an equidigital number, since it uses as much as digits as its factorization.

12102111001147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 112, while the sum is 22.

Adding to 12102111001147 its reverse (74110011120121), we get a palindrome (86212122121268).

The spelling of 12102111001147 in words is "twelve trillion, one hundred two billion, one hundred eleven million, one thousand, one hundred forty-seven".