Base | Representation |
---|---|
bin | 10001100111000110001… |
… | …100111110010111101111 |
3 | 11021200202200200202001122 |
4 | 101213012030332113233 |
5 | 124312003020201033 |
6 | 2323544023531155 |
7 | 153302105423213 |
oct | 21470614762757 |
9 | 4250680622048 |
10 | 1210211100143 |
11 | 42727a685831 |
12 | 1766692b9abb |
13 | 8a178c479b6 |
14 | 4280871c943 |
15 | 21731396a98 |
hex | 119c633e5ef |
1210211100143 has 2 divisors, whose sum is σ = 1210211100144. Its totient is φ = 1210211100142.
The previous prime is 1210211100113. The next prime is 1210211100167. The reversal of 1210211100143 is 3410011120121.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1210211100143 - 212 = 1210211096047 is a prime.
It is a super-2 number, since 2×12102111001432 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1210211100113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605105550071 + 605105550072.
It is an arithmetic number, because the mean of its divisors is an integer number (605105550072).
Almost surely, 21210211100143 is an apocalyptic number.
1210211100143 is a deficient number, since it is larger than the sum of its proper divisors (1).
1210211100143 is an equidigital number, since it uses as much as digits as its factorization.
1210211100143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 17.
Adding to 1210211100143 its reverse (3410011120121), we get a palindrome (4620222220264).
The spelling of 1210211100143 in words is "one trillion, two hundred ten billion, two hundred eleven million, one hundred thousand, one hundred forty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.075 sec. • engine limits •