Base | Representation |
---|---|
bin | 10001100111000111011… |
… | …100110001110001000101 |
3 | 11021200211011001120202112 |
4 | 101213013130301301011 |
5 | 124312023344120122 |
6 | 2323550052150405 |
7 | 153302451303155 |
oct | 21470734616105 |
9 | 4250734046675 |
10 | 1210232020037 |
11 | 4272904741a7 |
12 | 176674308405 |
13 | 8a180390a31 |
14 | 4280b406765 |
15 | 2173312a2e2 |
hex | 119c7731c45 |
1210232020037 has 2 divisors, whose sum is σ = 1210232020038. Its totient is φ = 1210232020036.
The previous prime is 1210232020003. The next prime is 1210232020051. The reversal of 1210232020037 is 7300202320121.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 824838138436 + 385393881601 = 908206^2 + 620801^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1210232020037 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1210232019994 and 1210232020021.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1210232020097) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605116010018 + 605116010019.
It is an arithmetic number, because the mean of its divisors is an integer number (605116010019).
Almost surely, 21210232020037 is an apocalyptic number.
It is an amenable number.
1210232020037 is a deficient number, since it is larger than the sum of its proper divisors (1).
1210232020037 is an equidigital number, since it uses as much as digits as its factorization.
1210232020037 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1008, while the sum is 23.
Adding to 1210232020037 its reverse (7300202320121), we get a palindrome (8510434340158).
The spelling of 1210232020037 in words is "one trillion, two hundred ten billion, two hundred thirty-two million, twenty thousand, thirty-seven".
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