Base | Representation |
---|---|
bin | 10001100111001011101… |
… | …011111100000010011011 |
3 | 11021201000002210222102201 |
4 | 101213023223330002123 |
5 | 124312200043300011 |
6 | 2324001111511031 |
7 | 153304303430413 |
oct | 21471353740233 |
9 | 4251002728381 |
10 | 1210303103131 |
11 | 427317604a61 |
12 | 176694088477 |
13 | 8a19201b535 |
14 | 42816a2b643 |
15 | 217394bbcc1 |
hex | 119cbafc09b |
1210303103131 has 2 divisors, whose sum is σ = 1210303103132. Its totient is φ = 1210303103130.
The previous prime is 1210303103129. The next prime is 1210303103237. The reversal of 1210303103131 is 1313013030121.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1210303103131 - 21 = 1210303103129 is a prime.
It is a super-2 number, since 2×12103031031312 (a number of 25 digits) contains 22 as substring.
Together with 1210303103129, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 1210303103099 and 1210303103108.
It is not a weakly prime, because it can be changed into another prime (1210303103431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605151551565 + 605151551566.
It is an arithmetic number, because the mean of its divisors is an integer number (605151551566).
Almost surely, 21210303103131 is an apocalyptic number.
1210303103131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1210303103131 is an equidigital number, since it uses as much as digits as its factorization.
1210303103131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 162, while the sum is 19.
Adding to 1210303103131 its reverse (1313013030121), we get a palindrome (2523316133252).
The spelling of 1210303103131 in words is "one trillion, two hundred ten billion, three hundred three million, one hundred three thousand, one hundred thirty-one".
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