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12103233311993 is a prime number
BaseRepresentation
bin1011000000100000000011…
…1011000001010011111001
31120212001120010202201021012
42300020000323001103321
53041244410211440433
641424052034123305
72356300255462415
oct260100073012371
946761503681235
1012103233311993
113946a5274607a
121435830420535
1369a43a032495
142dbb2a219d45
1515ec75e38848
hexb0200ec14f9

12103233311993 has 2 divisors, whose sum is σ = 12103233311994. Its totient is φ = 12103233311992.

The previous prime is 12103233311957. The next prime is 12103233312017. The reversal of 12103233311993 is 39911333230121.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11365778314489 + 737454997504 = 3371317^2 + 858752^2 .

It is a cyclic number.

It is not a de Polignac number, because 12103233311993 - 216 = 12103233246457 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 12103233311993.

It is not a weakly prime, because it can be changed into another prime (12103233311933) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6051616655996 + 6051616655997.

It is an arithmetic number, because the mean of its divisors is an integer number (6051616655997).

Almost surely, 212103233311993 is an apocalyptic number.

It is an amenable number.

12103233311993 is a deficient number, since it is larger than the sum of its proper divisors (1).

12103233311993 is an equidigital number, since it uses as much as digits as its factorization.

12103233311993 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 78732, while the sum is 41.

The spelling of 12103233311993 in words is "twelve trillion, one hundred three billion, two hundred thirty-three million, three hundred eleven thousand, nine hundred ninety-three".