Base | Representation |
---|---|
bin | 1011000000100000010110… |
… | …1000011010101110101111 |
3 | 1120212001202122102210212120 |
4 | 2300020011220122232233 |
5 | 3041300040423241310 |
6 | 41424103535404023 |
7 | 2356302235161615 |
oct | 260100550325657 |
9 | 46761678383776 |
10 | 12103312321455 |
11 | 3946a93300053 |
12 | 1435852983613 |
13 | 69a450506a44 |
14 | 2dbb369056b5 |
15 | 15ec7cd43b70 |
hex | b0205a1abaf |
12103312321455 has 32 divisors (see below), whose sum is σ = 19380165178368. Its totient is φ = 6450146640000.
The previous prime is 12103312321417. The next prime is 12103312321489. The reversal of 12103312321455 is 55412321330121.
It is a happy number.
It is not a de Polignac number, because 12103312321455 - 212 = 12103312317359 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 107350122 + ... + 107462808.
It is an arithmetic number, because the mean of its divisors is an integer number (605630161824).
Almost surely, 212103312321455 is an apocalyptic number.
12103312321455 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
12103312321455 is a deficient number, since it is larger than the sum of its proper divisors (7276852856913).
12103312321455 is a wasteful number, since it uses less digits than its factorization.
12103312321455 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 118127.
The product of its (nonzero) digits is 21600, while the sum is 33.
Adding to 12103312321455 its reverse (55412321330121), we get a palindrome (67515633651576).
The spelling of 12103312321455 in words is "twelve trillion, one hundred three billion, three hundred twelve million, three hundred twenty-one thousand, four hundred fifty-five".
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