12103323140131 has 2 divisors, whose sum is σ = 12103323140132. Its totient is φ = 12103323140130.

The previous prime is 12103323140099. The next prime is 12103323140141. The reversal of 12103323140131 is 13104132330121.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 12103323140131 - 2⁵ = 12103323140099 is a prime.

It is a super-2 number, since 2×12103323140131² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12103323140096 and 12103323140105.

It is not a weakly prime, because it can be changed into another prime (12103323140141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6051661570065 + 6051661570066.

It is an arithmetic number, because the mean of its divisors is an integer number (6051661570066).

Almost surely, 2^{12103323140131} is an apocalyptic number.

12103323140131 is a deficient number, since it is larger than the sum of its proper divisors (1).

12103323140131 is an equidigital number, since it uses as much as digits as its factorization.

12103323140131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 12103323140131 its reverse (13104132330121), we get a palindrome (25207455470252).

The spelling of 12103323140131 in words is "twelve trillion, one hundred three billion, three hundred twenty-three million, one hundred forty thousand, one hundred thirty-one".