1210441340031 has 32 divisors (see below), whose sum is σ = 2118065510400. Its totient is φ = 595705920480.

The previous prime is 1210441340029. The next prime is 1210441340089. The reversal of 1210441340031 is 1300431440121.

It is not a de Polignac number, because 1210441340031 - 2¹ = 1210441340029 is a prime.

It is a super-2 number, since 2×1210441340031² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1210441339983 and 1210441340010.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1210441330031) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 137890501 + ... + 137899278.

It is an arithmetic number, because the mean of its divisors is an integer number (66189547200).

Almost surely, 2^{1210441340031} is an apocalyptic number.

1210441340031 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

1210441340031 is a deficient number, since it is larger than the sum of its proper divisors (907624170369).

1210441340031 is a wasteful number, since it uses less digits than its factorization.

1210441340031 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 275789819.

The product of its (nonzero) digits is 1152, while the sum is 24.

Adding to 1210441340031 its reverse (1300431440121), we get a palindrome (2510872780152).

The spelling of 1210441340031 in words is "one trillion, two hundred ten billion, four hundred forty-one million, three hundred forty thousand, thirty-one".