Base | Representation |
---|---|
bin | 10110100011000100… |
… | …00100010110001001 |
3 | 1011020122021010111121 |
4 | 23101202010112021 |
5 | 144242424202213 |
6 | 5321110355241 |
7 | 605660244556 |
oct | 132142042611 |
9 | 34218233447 |
10 | 12105303433 |
11 | 5152145703 |
12 | 241a05bb21 |
13 | 11abc14252 |
14 | 82b9cda2d |
15 | 4acb2188d |
hex | 2d1884589 |
12105303433 has 2 divisors, whose sum is σ = 12105303434. Its totient is φ = 12105303432.
The previous prime is 12105303421. The next prime is 12105303451. The reversal of 12105303433 is 33430350121.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11962453129 + 142850304 = 109373^2 + 11952^2 .
It is a cyclic number.
It is not a de Polignac number, because 12105303433 - 233 = 3515368841 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12105303398 and 12105303407.
It is not a weakly prime, because it can be changed into another prime (12105303533) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6052651716 + 6052651717.
It is an arithmetic number, because the mean of its divisors is an integer number (6052651717).
Almost surely, 212105303433 is an apocalyptic number.
It is an amenable number.
12105303433 is a deficient number, since it is larger than the sum of its proper divisors (1).
12105303433 is an equidigital number, since it uses as much as digits as its factorization.
12105303433 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3240, while the sum is 25.
Adding to 12105303433 its reverse (33430350121), we get a palindrome (45535653554).
The spelling of 12105303433 in words is "twelve billion, one hundred five million, three hundred three thousand, four hundred thirty-three".
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