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12105642141331 is a prime number
BaseRepresentation
bin1011000000101001000001…
…1111111110011010010011
31120212021210000101220220121
42300022100133332122103
53041314323342010311
641425131043451111
72356414045261444
oct260122037763223
946767700356817
1012105642141331
113947a79439222
1214361a3086a97
1369a7320bcb9b
142dbcb80d72cb
1515ed67655b71
hexb02907fe693

12105642141331 has 2 divisors, whose sum is σ = 12105642141332. Its totient is φ = 12105642141330.

The previous prime is 12105642141301. The next prime is 12105642141377. The reversal of 12105642141331 is 13314124650121.

12105642141331 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12105642141331 is a prime.

It is a super-2 number, since 2×121056421413312 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (12105642141301) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6052821070665 + 6052821070666.

It is an arithmetic number, because the mean of its divisors is an integer number (6052821070666).

Almost surely, 212105642141331 is an apocalyptic number.

12105642141331 is a deficient number, since it is larger than the sum of its proper divisors (1).

12105642141331 is an equidigital number, since it uses as much as digits as its factorization.

12105642141331 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 17280, while the sum is 34.

Adding to 12105642141331 its reverse (13314124650121), we get a palindrome (25419766791452).

The spelling of 12105642141331 in words is "twelve trillion, one hundred five billion, six hundred forty-two million, one hundred forty-one thousand, three hundred thirty-one".