Base | Representation |
---|---|
bin | 1011000000101001000001… |
… | …1111111110011010010011 |
3 | 1120212021210000101220220121 |
4 | 2300022100133332122103 |
5 | 3041314323342010311 |
6 | 41425131043451111 |
7 | 2356414045261444 |
oct | 260122037763223 |
9 | 46767700356817 |
10 | 12105642141331 |
11 | 3947a79439222 |
12 | 14361a3086a97 |
13 | 69a7320bcb9b |
14 | 2dbcb80d72cb |
15 | 15ed67655b71 |
hex | b02907fe693 |
12105642141331 has 2 divisors, whose sum is σ = 12105642141332. Its totient is φ = 12105642141330.
The previous prime is 12105642141301. The next prime is 12105642141377. The reversal of 12105642141331 is 13314124650121.
12105642141331 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12105642141331 is a prime.
It is a super-2 number, since 2×121056421413312 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (12105642141301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6052821070665 + 6052821070666.
It is an arithmetic number, because the mean of its divisors is an integer number (6052821070666).
Almost surely, 212105642141331 is an apocalyptic number.
12105642141331 is a deficient number, since it is larger than the sum of its proper divisors (1).
12105642141331 is an equidigital number, since it uses as much as digits as its factorization.
12105642141331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 17280, while the sum is 34.
Adding to 12105642141331 its reverse (13314124650121), we get a palindrome (25419766791452).
The spelling of 12105642141331 in words is "twelve trillion, one hundred five billion, six hundred forty-two million, one hundred forty-one thousand, three hundred thirty-one".
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