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1210588342141 is a prime number
BaseRepresentation
bin10001100111011100101…
…100000010011101111101
311021201201222112121210111
4101213130230002131331
5124313241103422031
62324045301310021
7153314336061133
oct21473454023575
94251658477714
101210588342141
11427453617282
12176753705311
138a20914b709
144284287b753
15217545621b1
hex119dcb0277d

1210588342141 has 2 divisors, whose sum is σ = 1210588342142. Its totient is φ = 1210588342140.

The previous prime is 1210588342091. The next prime is 1210588342213. The reversal of 1210588342141 is 1412438850121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 855956182041 + 354632160100 = 925179^2 + 595510^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1210588342141 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1210588342094 and 1210588342103.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1210588342741) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605294171070 + 605294171071.

It is an arithmetic number, because the mean of its divisors is an integer number (605294171071).

Almost surely, 21210588342141 is an apocalyptic number.

It is an amenable number.

1210588342141 is a deficient number, since it is larger than the sum of its proper divisors (1).

1210588342141 is an equidigital number, since it uses as much as digits as its factorization.

1210588342141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 61440, while the sum is 40.

The spelling of 1210588342141 in words is "one trillion, two hundred ten billion, five hundred eighty-eight million, three hundred forty-two thousand, one hundred forty-one".