Base | Representation |
---|---|
bin | 111000011001000011… |
… | …1110101101100110011 |
3 | 102120120200000101220002 |
4 | 1300302013311230303 |
5 | 3441003100000201 |
6 | 131344345140215 |
7 | 11514654005432 |
oct | 1606207655463 |
9 | 376520011802 |
10 | 121100000051 |
11 | 473a387a478 |
12 | 1b57818a66b |
13 | b55c068084 |
14 | 5c0b485119 |
15 | 323b83b76b |
hex | 1c321f5b33 |
121100000051 has 2 divisors, whose sum is σ = 121100000052. Its totient is φ = 121100000050.
The previous prime is 121099999981. The next prime is 121100000057. The reversal of 121100000051 is 150000001121.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 121100000051 - 218 = 121099737907 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 121099999978 and 121100000041.
It is not a weakly prime, because it can be changed into another prime (121100000057) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60550000025 + 60550000026.
It is an arithmetic number, because the mean of its divisors is an integer number (60550000026).
Almost surely, 2121100000051 is an apocalyptic number.
121100000051 is a deficient number, since it is larger than the sum of its proper divisors (1).
121100000051 is an equidigital number, since it uses as much as digits as its factorization.
121100000051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10, while the sum is 11.
Adding to 121100000051 its reverse (150000001121), we get a palindrome (271100001172).
The spelling of 121100000051 in words is "one hundred twenty-one billion, one hundred million, fifty-one", and thus it is an aban number.
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