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12110010022133 is a prime number
BaseRepresentation
bin1011000000111001010011…
…0110000111100011110101
31120212201001102100020221122
42300032110312013203311
53041402300031202013
641431132314353325
72356630223534012
oct260162466074365
946781042306848
1012110010022133
11394990aa4a771
121437001a2b845
1369ac79cb843a
142dc1b0250709
15160020d47a08
hexb0394d878f5

12110010022133 has 2 divisors, whose sum is σ = 12110010022134. Its totient is φ = 12110010022132.

The previous prime is 12110010021959. The next prime is 12110010022151. The reversal of 12110010022133 is 33122001001121.

12110010022133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12043828858084 + 66181164049 = 3470422^2 + 257257^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12110010022133 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12110010022153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6055005011066 + 6055005011067.

It is an arithmetic number, because the mean of its divisors is an integer number (6055005011067).

Almost surely, 212110010022133 is an apocalyptic number.

It is an amenable number.

12110010022133 is a deficient number, since it is larger than the sum of its proper divisors (1).

12110010022133 is an equidigital number, since it uses as much as digits as its factorization.

12110010022133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 12110010022133 its reverse (33122001001121), we get a palindrome (45232011023254).

The spelling of 12110010022133 in words is "twelve trillion, one hundred ten billion, ten million, twenty-two thousand, one hundred thirty-three".