Base | Representation |
---|---|
bin | 1011000000111001010011… |
… | …1010010011111010010111 |
3 | 1120212201001111102002201122 |
4 | 2300032110322103322113 |
5 | 3041402300321340203 |
6 | 41431132354114155 |
7 | 2356630236062414 |
oct | 260162472237227 |
9 | 46781044362648 |
10 | 12110011121303 |
11 | 3949910630577 |
12 | 143700227b95b |
13 | 69ac7a2b1834 |
14 | 2dc1b045910b |
15 | 160020eb3538 |
hex | b0394e93e97 |
12110011121303 has 2 divisors, whose sum is σ = 12110011121304. Its totient is φ = 12110011121302.
The previous prime is 12110011121207. The next prime is 12110011121323. The reversal of 12110011121303 is 30312111001121.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12110011121303 - 212 = 12110011117207 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12110011121323) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6055005560651 + 6055005560652.
It is an arithmetic number, because the mean of its divisors is an integer number (6055005560652).
Almost surely, 212110011121303 is an apocalyptic number.
12110011121303 is a deficient number, since it is larger than the sum of its proper divisors (1).
12110011121303 is an equidigital number, since it uses as much as digits as its factorization.
12110011121303 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 36, while the sum is 17.
Adding to 12110011121303 its reverse (30312111001121), we get a palindrome (42422122122424).
The spelling of 12110011121303 in words is "twelve trillion, one hundred ten billion, eleven million, one hundred twenty-one thousand, three hundred three".
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