Base | Representation |
---|---|
bin | 1011000000111001010011… |
… | …1010101100000010011010 |
3 | 1120212201001111121010021121 |
4 | 2300032110322230002122 |
5 | 3041402300333020442 |
6 | 41431132400155454 |
7 | 2356630236653464 |
oct | 260162472540232 |
9 | 46781044533247 |
10 | 12110011220122 |
11 | 3949910698842 |
12 | 1437002308b8a |
13 | 69ac7a3177ca |
14 | 2dc1b0483134 |
15 | 160020ed2967 |
hex | b0394eac09a |
12110011220122 has 4 divisors (see below), whose sum is σ = 18165016830186. Its totient is φ = 6055005610060.
The previous prime is 12110011220051. The next prime is 12110011220143. The reversal of 12110011220122 is 22102211001121.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 11453682780241 + 656328439881 = 3384329^2 + 810141^2 .
It is a super-2 number, since 2×121100112201222 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 12110011220096 and 12110011220105.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3027502805029 + ... + 3027502805032.
Almost surely, 212110011220122 is an apocalyptic number.
12110011220122 is a deficient number, since it is larger than the sum of its proper divisors (6055005610064).
12110011220122 is an equidigital number, since it uses as much as digits as its factorization.
12110011220122 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6055005610063.
The product of its (nonzero) digits is 32, while the sum is 16.
Adding to 12110011220122 its reverse (22102211001121), we get a palindrome (34212222221243).
The spelling of 12110011220122 in words is "twelve trillion, one hundred ten billion, eleven million, two hundred twenty thousand, one hundred twenty-two".
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