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12110011989253 is a prime number
BaseRepresentation
bin1011000000111001010011…
…1101100111110100000101
31120212201001120001012022221
42300032110331213310011
53041402301032124003
641431132424452341
72356630246336033
oct260162475476405
946781046035287
1012110011989253
113949911073692
12143700261a0b1
1369ac7a526909
142dc1b0603553
151600210d57bd
hexb0394f67d05

12110011989253 has 2 divisors, whose sum is σ = 12110011989254. Its totient is φ = 12110011989252.

The previous prime is 12110011989221. The next prime is 12110011989307. The reversal of 12110011989253 is 35298911001121.

12110011989253 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8055418974849 + 4054593014404 = 2838207^2 + 2013602^2 .

It is a cyclic number.

It is not a de Polignac number, because 12110011989253 - 25 = 12110011989221 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12110011981253) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6055005994626 + 6055005994627.

It is an arithmetic number, because the mean of its divisors is an integer number (6055005994627).

Almost surely, 212110011989253 is an apocalyptic number.

It is an amenable number.

12110011989253 is a deficient number, since it is larger than the sum of its proper divisors (1).

12110011989253 is an equidigital number, since it uses as much as digits as its factorization.

12110011989253 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 38880, while the sum is 43.

The spelling of 12110011989253 in words is "twelve trillion, one hundred ten billion, eleven million, nine hundred eighty-nine thousand, two hundred fifty-three".