12110013133 has 2 divisors, whose sum is σ = 12110013134. Its totient is φ = 12110013132.

The previous prime is 12110013119. The next prime is 12110013193. The reversal of 12110013133 is 33131001121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7299480969 + 4810532164 = 85437^2 + 69358^2 .

It is a cyclic number.

It is not a de Polignac number, because 12110013133 - 2¹³ = 12110004941 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12110013103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6055006566 + 6055006567.

It is an arithmetic number, because the mean of its divisors is an integer number (6055006567).

Almost surely, 2^12110013133 is an apocalyptic number.

It is an amenable number.

12110013133 is a deficient number, since it is larger than the sum of its proper divisors (1).

12110013133 is an equidigital number, since it uses as much as digits as its factorization.

12110013133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 12110013133 its reverse (33131001121), we get a palindrome (45241014254).

The spelling of 12110013133 in words is "twelve billion, one hundred ten million, thirteen thousand, one hundred thirty-three".