12110100101117 has 2 divisors, whose sum is σ = 12110100101118. Its totient is φ = 12110100101116.

The previous prime is 12110100101083. The next prime is 12110100101149. The reversal of 12110100101117 is 71110100101121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12110079842116 + 20259001 = 3479954^2 + 4501^2 .

It is an emirp because it is prime and its reverse (71110100101121) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12110100101117 - 2¹⁰ = 12110100100093 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12110100101095 and 12110100101104.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12110100151117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6055050050558 + 6055050050559.

It is an arithmetic number, because the mean of its divisors is an integer number (6055050050559).

Almost surely, 2^{12110100101117} is an apocalyptic number.

It is an amenable number.

12110100101117 is a deficient number, since it is larger than the sum of its proper divisors (1).

12110100101117 is an equidigital number, since it uses as much as digits as its factorization.

12110100101117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 14, while the sum is 17.

Adding to 12110100101117 its reverse (71110100101121), we get a palindrome (83220200202238).

The spelling of 12110100101117 in words is "twelve trillion, one hundred ten billion, one hundred million, one hundred one thousand, one hundred seventeen".