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121101220117 is a prime number
BaseRepresentation
bin111000011001000110…
…0011111100100010101
3102120120202022101111201
41300302030133210111
53441003403020432
6131344431232501
711515000246453
oct1606214374425
9376522271451
10121101220117
11473a4533099
121b578678731
13b55c3a44c7
145c0b6c19d3
15323b9ccee7
hex1c3231f915

121101220117 has 2 divisors, whose sum is σ = 121101220118. Its totient is φ = 121101220116.

The previous prime is 121101220109. The next prime is 121101220129. The reversal of 121101220117 is 711022101121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 121058068356 + 43151761 = 347934^2 + 6569^2 .

It is a cyclic number.

It is not a de Polignac number, because 121101220117 - 23 = 121101220109 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 121101220094 and 121101220103.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (121101220157) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60550610058 + 60550610059.

It is an arithmetic number, because the mean of its divisors is an integer number (60550610059).

Almost surely, 2121101220117 is an apocalyptic number.

It is an amenable number.

121101220117 is a deficient number, since it is larger than the sum of its proper divisors (1).

121101220117 is an equidigital number, since it uses as much as digits as its factorization.

121101220117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 56, while the sum is 19.

Adding to 121101220117 its reverse (711022101121), we get a palindrome (832123321238).

The spelling of 121101220117 in words is "one hundred twenty-one billion, one hundred one million, two hundred twenty thousand, one hundred seventeen".