12110122112147 has 2 divisors, whose sum is σ = 12110122112148. Its totient is φ = 12110122112146.

The previous prime is 12110122112129. The next prime is 12110122112149. The reversal of 12110122112147 is 74121122101121.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 12110122112147 - 2⁶ = 12110122112083 is a prime.

It is a super-3 number, since 3×12110122112147³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 12110122112149, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (12110122112149) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6055061056073 + 6055061056074.

It is an arithmetic number, because the mean of its divisors is an integer number (6055061056074).

Almost surely, 2^{12110122112147} is an apocalyptic number.

12110122112147 is a deficient number, since it is larger than the sum of its proper divisors (1).

12110122112147 is an equidigital number, since it uses as much as digits as its factorization.

12110122112147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 448, while the sum is 26.

Adding to 12110122112147 its reverse (74121122101121), we get a palindrome (86231244213268).

The spelling of 12110122112147 in words is "twelve trillion, one hundred ten billion, one hundred twenty-two million, one hundred twelve thousand, one hundred forty-seven".