Base | Representation |
---|---|
bin | 1011000000111001101110… |
… | …0010100000110100111111 |
3 | 1120212201100020122202010202 |
4 | 2300032123202200310333 |
5 | 3041403012303321023 |
6 | 41431151405354115 |
7 | 2356633056221366 |
oct | 260163342406477 |
9 | 46781306582122 |
10 | 12110122323263 |
11 | 3949968383218 |
12 | 143703356893b |
13 | 69ac97348003 |
14 | 2dc1c11247dd |
15 | 16002ab2c128 |
hex | b039b8a0d3f |
12110122323263 has 2 divisors, whose sum is σ = 12110122323264. Its totient is φ = 12110122323262.
The previous prime is 12110122323253. The next prime is 12110122323281. The reversal of 12110122323263 is 36232322101121.
12110122323263 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12110122323263 - 236 = 12041402846527 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12110122323253) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6055061161631 + 6055061161632.
It is an arithmetic number, because the mean of its divisors is an integer number (6055061161632).
Almost surely, 212110122323263 is an apocalyptic number.
12110122323263 is a deficient number, since it is larger than the sum of its proper divisors (1).
12110122323263 is an equidigital number, since it uses as much as digits as its factorization.
12110122323263 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 29.
Adding to 12110122323263 its reverse (36232322101121), we get a palindrome (48342444424384).
The spelling of 12110122323263 in words is "twelve trillion, one hundred ten billion, one hundred twenty-two million, three hundred twenty-three thousand, two hundred sixty-three".
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