Base | Representation |
---|---|
bin | 1011000000111010000011… |
… | …0001110001110010100111 |
3 | 1120212201120101000220102111 |
4 | 2300032200301301302213 |
5 | 3041403202303222413 |
6 | 41431204225221451 |
7 | 2356635204235663 |
oct | 260164061616247 |
9 | 46781511026374 |
10 | 12110210210983 |
11 | 3949a02a515a5 |
12 | 1437058a91887 |
13 | 69acac60a691 |
14 | 2dc1cca818a3 |
15 | 1600336dcd3d |
hex | b03a0c71ca7 |
12110210210983 has 2 divisors, whose sum is σ = 12110210210984. Its totient is φ = 12110210210982.
The previous prime is 12110210210977. The next prime is 12110210211013. The reversal of 12110210210983 is 38901201201121.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12110210210983 - 213 = 12110210202791 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12110210210183) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6055105105491 + 6055105105492.
It is an arithmetic number, because the mean of its divisors is an integer number (6055105105492).
Almost surely, 212110210210983 is an apocalyptic number.
12110210210983 is a deficient number, since it is larger than the sum of its proper divisors (1).
12110210210983 is an equidigital number, since it uses as much as digits as its factorization.
12110210210983 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 31.
The spelling of 12110210210983 in words is "twelve trillion, one hundred ten billion, two hundred ten million, two hundred ten thousand, nine hundred eighty-three".
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