Base | Representation |
---|---|
bin | 1011000000111010000011… |
… | …0100110010011110010011 |
3 | 1120212201120102112000001011 |
4 | 2300032200310302132103 |
5 | 3041403203004001321 |
6 | 41431204254151351 |
7 | 2356635214033642 |
oct | 260164064623623 |
9 | 46781512460034 |
10 | 12110211000211 |
11 | 3949a03440555 |
12 | 14370591b2557 |
13 | 69acac82598c |
14 | 2dc1ccc09359 |
15 | 1600337e6ae1 |
hex | b03a0d32793 |
12110211000211 has 2 divisors, whose sum is σ = 12110211000212. Its totient is φ = 12110211000210.
The previous prime is 12110211000197. The next prime is 12110211000253. The reversal of 12110211000211 is 11200011201121.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12110211000211 - 29 = 12110210999699 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12110211000191 and 12110211000200.
It is not a weakly prime, because it can be changed into another prime (12110211000271) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6055105500105 + 6055105500106.
It is an arithmetic number, because the mean of its divisors is an integer number (6055105500106).
Almost surely, 212110211000211 is an apocalyptic number.
12110211000211 is a deficient number, since it is larger than the sum of its proper divisors (1).
12110211000211 is an equidigital number, since it uses as much as digits as its factorization.
12110211000211 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8, while the sum is 13.
Adding to 12110211000211 its reverse (11200011201121), we get a palindrome (23310222201332).
The spelling of 12110211000211 in words is "twelve trillion, one hundred ten billion, two hundred eleven million, two hundred eleven", and thus it is an aban number.
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