12110211002051 has 2 divisors, whose sum is σ = 12110211002052. Its totient is φ = 12110211002050.

The previous prime is 12110211001979. The next prime is 12110211002053. The reversal of 12110211002051 is 15020011201121.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 12110211002051 - 2¹⁴ = 12110210985667 is a prime.

Together with 12110211002053, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (12110211002053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6055105501025 + 6055105501026.

It is an arithmetic number, because the mean of its divisors is an integer number (6055105501026).

Almost surely, 2^{12110211002051} is an apocalyptic number.

12110211002051 is a deficient number, since it is larger than the sum of its proper divisors (1).

12110211002051 is an equidigital number, since it uses as much as digits as its factorization.

12110211002051 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 40, while the sum is 17.

Adding to 12110211002051 its reverse (15020011201121), we get a palindrome (27130222203172).

The spelling of 12110211002051 in words is "twelve trillion, one hundred ten billion, two hundred eleven million, two thousand, fifty-one".