Base | Representation |
---|---|
bin | 11011100010010001001000… |
… | …010111111001001100000010 |
3 | 120212210020201102010122201200 |
4 | 123202101020113321030002 |
5 | 111333114111144213442 |
6 | 1105321313044042030 |
7 | 34336224142366005 |
oct | 3342211027711402 |
9 | 525706642118650 |
10 | 121102112101122 |
11 | 35650132179019 |
12 | 116ba498393316 |
13 | 5275b5996bb09 |
14 | 21c9532c5353c |
15 | e0022575e34c |
hex | 6e24485f9302 |
121102112101122 has 12 divisors (see below), whose sum is σ = 262387909552470. Its totient is φ = 40367370700368.
The previous prime is 121102112101099. The next prime is 121102112101123. The reversal of 121102112101122 is 221101211201121.
It is a happy number.
121102112101122 is a `hidden beast` number, since 1 + 211 + 0 + 211 + 210 + 11 + 22 = 666.
It can be written as a sum of positive squares in only one way, i.e., 80370669170961 + 40731442930161 = 8964969^2 + 6382119^2 .
It is a Harshad number since it is a multiple of its sum of digits (18), and also a Moran number because the ratio is a prime number: 6727895116729 = 121102112101122 / (1 + 2 + 1 + 1 + 0 + 2 + 1 + 1 + 2 + 1 + 0 + 1 + 1 + 2 + 2).
It is a junction number, because it is equal to n+sod(n) for n = 121102112101095 and 121102112101104.
It is not an unprimeable number, because it can be changed into a prime (121102112101123) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 3363947558347 + ... + 3363947558382.
Almost surely, 2121102112101122 is an apocalyptic number.
121102112101122 is an abundant number, since it is smaller than the sum of its proper divisors (141285797451348).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
121102112101122 is a wasteful number, since it uses less digits than its factorization.
121102112101122 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6727895116737 (or 6727895116734 counting only the distinct ones).
The product of its (nonzero) digits is 32, while the sum is 18.
Adding to 121102112101122 its reverse (221101211201121), we get a palindrome (342203323302243).
Subtracting 121102112101122 from its reverse (221101211201121), we obtain a palindrome (99999099099999).
The spelling of 121102112101122 in words is "one hundred twenty-one trillion, one hundred two billion, one hundred twelve million, one hundred one thousand, one hundred twenty-two".
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