Base | Representation |
---|---|
bin | 10001100111110110100… |
… | …010010100001110111001 |
3 | 11021202212012112210000201 |
4 | 101213312202110032321 |
5 | 124320133113013311 |
6 | 2324200312202201 |
7 | 153331153110664 |
oct | 21476642241671 |
9 | 4252765483021 |
10 | 1211022001081 |
11 | 4276563916a2 |
12 | 176854999361 |
13 | 8a277c46539 |
14 | 428842c46db |
15 | 2177c6739c1 |
hex | 119f68943b9 |
1211022001081 has 2 divisors, whose sum is σ = 1211022001082. Its totient is φ = 1211022001080.
The previous prime is 1211022001073. The next prime is 1211022001097. The reversal of 1211022001081 is 1801002201121.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1194520029481 + 16501971600 = 1092941^2 + 128460^2 .
It is a cyclic number.
It is not a de Polignac number, because 1211022001081 - 23 = 1211022001073 is a prime.
It is a super-2 number, since 2×12110220010812 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1211022002081) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605511000540 + 605511000541.
It is an arithmetic number, because the mean of its divisors is an integer number (605511000541).
Almost surely, 21211022001081 is an apocalyptic number.
It is an amenable number.
1211022001081 is a deficient number, since it is larger than the sum of its proper divisors (1).
1211022001081 is an equidigital number, since it uses as much as digits as its factorization.
1211022001081 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 64, while the sum is 19.
The spelling of 1211022001081 in words is "one trillion, two hundred eleven billion, twenty-two million, one thousand, eighty-one".
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