Base | Representation |
---|---|
bin | 11011100010010001011100… |
… | …000011001010001011111111 |
3 | 120212210021120102021221001011 |
4 | 123202101130003022023333 |
5 | 111333120300201210142 |
6 | 1105321405515300051 |
7 | 34336235261306464 |
oct | 3342213403121377 |
9 | 525707512257034 |
10 | 121102442210047 |
11 | 35650291547811 |
12 | 116ba56aa4a627 |
13 | 5275bb017c33c |
14 | 21c9564a2366b |
15 | e00244719417 |
hex | 6e245c0ca2ff |
121102442210047 has 2 divisors, whose sum is σ = 121102442210048. Its totient is φ = 121102442210046.
The previous prime is 121102442209999. The next prime is 121102442210069. The reversal of 121102442210047 is 740012244201121.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-121102442210047 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (121102442210447) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60551221105023 + 60551221105024.
It is an arithmetic number, because the mean of its divisors is an integer number (60551221105024).
Almost surely, 2121102442210047 is an apocalyptic number.
121102442210047 is a deficient number, since it is larger than the sum of its proper divisors (1).
121102442210047 is an equidigital number, since it uses as much as digits as its factorization.
121102442210047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7168, while the sum is 31.
Adding to 121102442210047 its reverse (740012244201121), we get a palindrome (861114686411168).
The spelling of 121102442210047 in words is "one hundred twenty-one trillion, one hundred two billion, four hundred forty-two million, two hundred ten thousand, forty-seven".
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