12110311303002 has 24 divisors (see below), whose sum is σ = 28624372171200. Its totient is φ = 3669791303880.

The previous prime is 12110311302937. The next prime is 12110311303003. The reversal of 12110311303002 is 20030311301121.

12110311303002 is a `hidden beast` number, since 1 + 21 + 1 + 0 + 311 + 30 + 300 + 2 = 666.

It is a super-3 number, since 3×12110311303002³ (a number of 40 digits) contains 333 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is not an unprimeable number, because it can be changed into a prime (12110311303003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 30581594002 + ... + 30581594397.

It is an arithmetic number, because the mean of its divisors is an integer number (1192682173800).

Almost surely, 2^{12110311303002} is an apocalyptic number.

12110311303002 is an abundant number, since it is smaller than the sum of its proper divisors (16514060868198).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12110311303002 is a wasteful number, since it uses less digits than its factorization.

12110311303002 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 61163188418 (or 61163188415 counting only the distinct ones).

The product of its (nonzero) digits is 108, while the sum is 18.

Adding to 12110311303002 its reverse (20030311301121), we get a palindrome (32140622604123).

The spelling of 12110311303002 in words is "twelve trillion, one hundred ten billion, three hundred eleven million, three hundred three thousand, two".