1211031212113 has 2 divisors, whose sum is σ = 1211031212114. Its totient is φ = 1211031212112.

The previous prime is 1211031212087. The next prime is 1211031212147. The reversal of 1211031212113 is 3112121301121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 836012149569 + 375019062544 = 914337^2 + 612388^2 .

It is a cyclic number.

It is not a de Polignac number, because 1211031212113 - 2⁵ = 1211031212081 is a prime.

It is not a weakly prime, because it can be changed into another prime (1211031212513) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605515606056 + 605515606057.

It is an arithmetic number, because the mean of its divisors is an integer number (605515606057).

Almost surely, 2^{1211031212113} is an apocalyptic number.

It is an amenable number.

1211031212113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1211031212113 is an equidigital number, since it uses as much as digits as its factorization.

1211031212113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72, while the sum is 19.

Adding to 1211031212113 its reverse (3112121301121), we get a palindrome (4323152513234).

The spelling of 1211031212113 in words is "one trillion, two hundred eleven billion, thirty-one million, two hundred twelve thousand, one hundred thirteen".