Base | Representation |
---|---|
bin | 10001100111110111000… |
… | …101011101000001110011 |
3 | 11021202212211212202020022 |
4 | 101213313011131001303 |
5 | 124320142442242042 |
6 | 2324201241434055 |
7 | 153331324313261 |
oct | 21476705350163 |
9 | 4252784782208 |
10 | 1211031212147 |
11 | 427660603049 |
12 | 176857a9b92b |
13 | 8a279b1cc83 |
14 | 42885601431 |
15 | 2177d392cd2 |
hex | 119f715d073 |
1211031212147 has 2 divisors, whose sum is σ = 1211031212148. Its totient is φ = 1211031212146.
The previous prime is 1211031212113. The next prime is 1211031212197. The reversal of 1211031212147 is 7412121301121.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1211031212147 - 28 = 1211031211891 is a prime.
It is not a weakly prime, because it can be changed into another prime (1211031212197) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605515606073 + 605515606074.
It is an arithmetic number, because the mean of its divisors is an integer number (605515606074).
Almost surely, 21211031212147 is an apocalyptic number.
1211031212147 is a deficient number, since it is larger than the sum of its proper divisors (1).
1211031212147 is an equidigital number, since it uses as much as digits as its factorization.
1211031212147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 672, while the sum is 26.
Adding to 1211031212147 its reverse (7412121301121), we get a palindrome (8623152513268).
The spelling of 1211031212147 in words is "one trillion, two hundred eleven billion, thirty-one million, two hundred twelve thousand, one hundred forty-seven".
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