Base | Representation |
---|---|
bin | 10110100011101010… |
… | …01011011110010111 |
3 | 1011020222200122211201 |
4 | 23101311023132113 |
5 | 144300220011432 |
6 | 5321410013331 |
7 | 606050652025 |
oct | 132165133627 |
9 | 34228618751 |
10 | 12110313367 |
11 | 5154a57749 |
12 | 241b877247 |
13 | 11acc796c9 |
14 | 82c535715 |
15 | 4ad2b0ee7 |
hex | 2d1d4b797 |
12110313367 has 2 divisors, whose sum is σ = 12110313368. Its totient is φ = 12110313366.
The previous prime is 12110313359. The next prime is 12110313373. The reversal of 12110313367 is 76331301121.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12110313367 - 23 = 12110313359 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12110313317) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6055156683 + 6055156684.
It is an arithmetic number, because the mean of its divisors is an integer number (6055156684).
Almost surely, 212110313367 is an apocalyptic number.
12110313367 is a deficient number, since it is larger than the sum of its proper divisors (1).
12110313367 is an equidigital number, since it uses as much as digits as its factorization.
12110313367 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2268, while the sum is 28.
Adding to 12110313367 its reverse (76331301121), we get a palindrome (88441614488).
The spelling of 12110313367 in words is "twelve billion, one hundred ten million, three hundred thirteen thousand, three hundred sixty-seven".
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