Base | Representation |
---|---|
bin | 11011100010010010001001… |
… | …010101111010101100001111 |
3 | 120212210100112101011102212201 |
4 | 123202102021111322230033 |
5 | 111333123324214231111 |
6 | 1105322013142342331 |
7 | 34336263146265142 |
oct | 3342221125725417 |
9 | 525710471142781 |
10 | 121103202102031 |
11 | 35650641483916 |
12 | 116ba74142a9a7 |
13 | 5275ca172b476 |
14 | 21c95d790c059 |
15 | e0028b2bc6c1 |
hex | 6e248957ab0f |
121103202102031 has 2 divisors, whose sum is σ = 121103202102032. Its totient is φ = 121103202102030.
The previous prime is 121103202102011. The next prime is 121103202102163. The reversal of 121103202102031 is 130201202301121.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 121103202102031 - 223 = 121103193713423 is a prime.
It is a super-2 number, since 2×1211032021020312 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (121103202102011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60551601051015 + 60551601051016.
It is an arithmetic number, because the mean of its divisors is an integer number (60551601051016).
Almost surely, 2121103202102031 is an apocalyptic number.
121103202102031 is a deficient number, since it is larger than the sum of its proper divisors (1).
121103202102031 is an equidigital number, since it uses as much as digits as its factorization.
121103202102031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 121103202102031 its reverse (130201202301121), we get a palindrome (251304404403152).
The spelling of 121103202102031 in words is "one hundred twenty-one trillion, one hundred three billion, two hundred two million, one hundred two thousand, thirty-one".
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