Base | Representation |
---|---|
bin | 10001100111110111001… |
… | …100110110000000101001 |
3 | 11021202212222112011202102 |
4 | 101213313030312000221 |
5 | 124320143441240411 |
6 | 2324201351143145 |
7 | 153331346632421 |
oct | 21476714660051 |
9 | 4252788464672 |
10 | 1211033149481 |
11 | 427661706651 |
12 | 176858674ab5 |
13 | 8a27a34aa1c |
14 | 42885987481 |
15 | 2177d626d3b |
hex | 119f7336029 |
1211033149481 has 2 divisors, whose sum is σ = 1211033149482. Its totient is φ = 1211033149480.
The previous prime is 1211033149433. The next prime is 1211033149489. The reversal of 1211033149481 is 1849413301121.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 817910419456 + 393122730025 = 904384^2 + 626995^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1211033149481 is a prime.
It is a super-2 number, since 2×12110331494812 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1211033149489) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605516574740 + 605516574741.
It is an arithmetic number, because the mean of its divisors is an integer number (605516574741).
Almost surely, 21211033149481 is an apocalyptic number.
It is an amenable number.
1211033149481 is a deficient number, since it is larger than the sum of its proper divisors (1).
1211033149481 is an equidigital number, since it uses as much as digits as its factorization.
1211033149481 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20736, while the sum is 38.
The spelling of 1211033149481 in words is "one trillion, two hundred eleven billion, thirty-three million, one hundred forty-nine thousand, four hundred eighty-one".
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