Base | Representation |
---|---|
bin | 10110100011101011… |
… | …00000100111101101 |
3 | 1011020222212001122122 |
4 | 23101311200213231 |
5 | 144300230244411 |
6 | 5321411522325 |
7 | 606051462401 |
oct | 132165404755 |
9 | 34228761578 |
10 | 12110399981 |
11 | 5155006829 |
12 | 241b8b93a5 |
13 | 11acca9c64 |
14 | 82c559101 |
15 | 4ad2cb9db |
hex | 2d1d609ed |
12110399981 has 2 divisors, whose sum is σ = 12110399982. Its totient is φ = 12110399980.
The previous prime is 12110399963. The next prime is 12110400017. The reversal of 12110399981 is 18999301121.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11216928100 + 893471881 = 105910^2 + 29891^2 .
It is an emirp because it is prime and its reverse (18999301121) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12110399981 - 210 = 12110398957 is a prime.
It is a super-2 number, since 2×121103999812 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12110399381) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6055199990 + 6055199991.
It is an arithmetic number, because the mean of its divisors is an integer number (6055199991).
Almost surely, 212110399981 is an apocalyptic number.
It is an amenable number.
12110399981 is a deficient number, since it is larger than the sum of its proper divisors (1).
12110399981 is an equidigital number, since it uses as much as digits as its factorization.
12110399981 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 34992, while the sum is 44.
The spelling of 12110399981 in words is "twelve billion, one hundred ten million, three hundred ninety-nine thousand, nine hundred eighty-one".
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